Find two consecutive integers whose product is 6 less than the square of the smaller number

Question

Find two consecutive integers whose product is 6 less than the square of the smaller number

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Edana Edana 2 months 2021-07-24T15:27:14+00:00 1 Answers 11 views 0

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    2021-07-24T15:28:36+00:00

    Answer:

    Hi there!

    Your answer is:

    The smaller integer is -6

    The larger integer is -5

    Step-by-step explanation:

    Two consecutive integers:

    x, x+1

    Product= multiply

    (x) × (x+1) = x^2 – 6

    x^2 + x= x^2 -6

    -x^2

    x= -6

    Plug back in

    First integer (smaller):

    -6

    Second integer (larger):

    -6+1

    -5

    Check your work!

    (-6) × (-6+1)

    (-6)× (-5)

    30 = (-6)^2 -6

    30 = 36-6

    30= 30 ✓✓✓✓

    That’s how we determine that this is the correct answer

    Hopefully this helps

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )