## Find three consecutive odd integers whose sum is-213.

Question

Find three consecutive odd integers whose sum is-213.

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18 hours 2021-07-22T19:47:52+00:00 2 Answers 0 views 0

1. x + x + 2 + x + 4 = -213
3x + 6 = -213
3x = -219
x = -73
-73 + 2 = -71
-73 + 4 = -69
Solution: -73, -71, -69

first odd number be x = – 73

second odd number be x + 2 = (- 73 + 2) = – 71

third odd number be x + 4 = (- 73 + 4) = – 69

Step-by-step explanation:

let the first odd number be x

second odd number be x + 2

third odd number be x + 4

Now, three consecutive odd integers whose sum is – 213.

i.e.,

(x) + (x + 2) + (x + 4) = – 213

Then,

(x) + (x + 2) + (x + 4) = – 213

x + x + 2 + x + 4 = – 213

3x + 6 = – 213

3x = – 213 – 6

3x = – 219

x = – 219/3

x = 73

Thus, The value of x is 73

Here,

first odd number be x = 73

second odd number be x + 2 = (- 73 + 2) = 71

third odd number be x + 4 = (- 73 + 4) = 69

So

(x) + (x + 2) + (x + 4) = – 213

(- 73) + (- 73 + 2) + (- 73 + 4) = – 213

(- 73) + (- 71) + (- 69) = – 213

– 73 – 71 – 69 = – 213

– 213 = – 213

Hence, L.H.S = R.H.S

-TheUnknownScientist

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