Find three consecutive odd integers whose sum is-213.

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Find three consecutive odd integers whose sum is-213.

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  2. Answer:

    first odd number be x = – 73

    second odd number be x + 2 = (- 73 + 2) = – 71

    third odd number be x + 4 = (- 73 + 4) = – 69

    Step-by-step explanation:

    let the first odd number be x

    second odd number be x + 2

    third odd number be x + 4

    Now, three consecutive odd integers whose sum is – 213.

    i.e.,

    (x) + (x + 2) + (x + 4) = – 213

    Then,

    (x) + (x + 2) + (x + 4) = – 213

    x + x + 2 + x + 4 = – 213

    3x + 6 = – 213

    3x = – 213 – 6

    3x = – 219

    x = – 219/3

    x = – 73

    Thus, The value of x is – 73

    Here,

    first odd number be x = – 73

    second odd number be x + 2 = (- 73 + 2) = – 71

    third odd number be x + 4 = (- 73 + 4) = – 69

    So

    (x) + (x + 2) + (x + 4) = – 213

    (- 73) + (- 73 + 2) + (- 73 + 4) = – 213

    (- 73) + (- 71) + (- 69) = – 213

    – 73 – 71 – 69 = – 213

    – 213 = – 213

    Hence, L.H.S = R.H.S

    -TheUnknownScientist

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