Find three consecutive odd integers whose sum is-213.

Question

Find three consecutive odd integers whose sum is-213.

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Gia Bảo 18 hours 2021-07-22T19:47:52+00:00 2 Answers 0 views 0

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    0
    2021-07-22T19:48:58+00:00

    x + x + 2 + x + 4 = -213
    3x + 6 = -213
    3x = -219
    x = -73
    -73 + 2 = -71
    -73 + 4 = -69
    Solution: -73, -71, -69

    0
    2021-07-22T19:49:22+00:00

    Answer:

    first odd number be x = – 73

    second odd number be x + 2 = (- 73 + 2) = – 71

    third odd number be x + 4 = (- 73 + 4) = – 69

    Step-by-step explanation:

    let the first odd number be x

    second odd number be x + 2

    third odd number be x + 4

    Now, three consecutive odd integers whose sum is – 213.

    i.e.,

    (x) + (x + 2) + (x + 4) = – 213

    Then,

    (x) + (x + 2) + (x + 4) = – 213

    x + x + 2 + x + 4 = – 213

    3x + 6 = – 213

    3x = – 213 – 6

    3x = – 219

    x = – 219/3

    x = 73

    Thus, The value of x is 73

    Here,

    first odd number be x = 73

    second odd number be x + 2 = (- 73 + 2) = 71

    third odd number be x + 4 = (- 73 + 4) = 69

    So

    (x) + (x + 2) + (x + 4) = – 213

    (- 73) + (- 73 + 2) + (- 73 + 4) = – 213

    (- 73) + (- 71) + (- 69) = – 213

    – 73 – 71 – 69 = – 213

    – 213 = – 213

    Hence, L.H.S = R.H.S

    -TheUnknownScientist

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )