Find the total surface area of this prism where the cross section is an isosceles triangle 5cm, 13cm, 24cm, 10cm

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Find the total surface area of this prism where the cross section is an isosceles triangle 5cm, 13cm, 24cm, 10cm

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Tryphena 4 years 2021-09-04T06:55:35+00:00 1 Answers 48 views 0

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  1. diemthu
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    2021-09-04T06:56:37+00:00
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    Answer: 620 cm2


    Step-by-step explanation:


    The base of the prism is a rectangle with 24 cm x 10 cm, so the base area is:  B = 24 * 10 = 240 cm2

    The cross section is a triangle with base = 24 cm and height = 5 cm, so its area is:  C = 24 * 5 / 2 = 60 cm2


    The sides are rectangles with 10 cm x 13 cm, so their area is:  D = 10 * 13 = 130 cm2


    The total surface area is:  S = B + 2C + 2D = 240 + 2*60 + 2*130 = 620 cm2


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