Find the total pressure (in atm) of a mixture that contains 3 gases with the following partial pressures. Gas A is 4.2atm, Gas B is 780 mmHg

Question

Find the total pressure (in atm) of a mixture that contains 3 gases with the following partial pressures. Gas A is 4.2atm, Gas B is 780 mmHg, Gas C is 250.00kPa

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niczorrrr 3 months 2021-08-15T07:51:18+00:00 1 Answers 0 views 0

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    2021-08-15T07:52:24+00:00

    Answer: The total pressure of given mixture that contains 3 gases is 7.68 atm.

    Explanation:

    Given: Partial pressure of gases is:

    Gas A = 4.2 atm

    Gas B = 780 mm Hg

    Convert mm Hg into atm is as follows.

    1 mm Hg = 0.00131579 atm\\780 mm Hg = 780 mm Hg \times \frac{0.00131579 atm}{1 mm Hg}\\= 1.02 atm

    Gas C = 250 kPa

    Convert kPa into atm as follows.

    1 kPa = 0.00986923 atm\\250 kPa = 250 kPa \times \frac{0.00986923 atm}{1 kPa}\\= 2.46 atm

    Total pressure is the sum of partial pressures of gases present in the mixture.

    Therefore, total pressure of given mixture is calculated as follows.

    P_{total} = P_{A} + P_{B} + P_{C}\\= 4.2 atm + 1.02 atm + 2.46 atm\\= 7.68 atm

    Thus, we can conclude that the total pressure of given mixture that contains 3 gases is 7.68 atm.

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