Find the roots of h(t) = (139kt)^2 − 69t + 80 the smaller root is: the larger root is: The answers will consist of

Question

Find the roots of h(t) = (139kt)^2 − 69t + 80
the smaller root is:
the larger root is:

The answers will consist of algebraic expressions containing the parameter k.

What positive value of k will result in exactly one real root?
K = ?

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Eirian 5 years 2021-08-20T20:02:06+00:00 1 Answers 14 views 0

Answers ( )

  1. Jezebel
    0
    2021-08-20T20:03:36+00:00
    Reply

    Step-by-step explanation:

    Given

    h(t)=(139kt)^2-69t+80

    For roots h(t)=0

    (139kt)^2-69t+80=0\\t=\dfrac{69\pm\sqrt{(-69)^2-4\times (139k)^2(80)}}{2\times 139}\\

    t=\dfrac{69\pm\sqrt{4761-6182720k^2}}{278}

    Larger root: t=\dfrac{69+\sqrt{4761-6182720k^2}}{278}

    smaller root: t=\dfrac{69-\sqrt{4761-6182720k^2}}{278}

    For exactly one root D=0

    i.e. 4761-6182720k^2=0\\\\k=\dfrac{69}{139\times 4\times 2\times \sqrt{5}}\\k=0.0277

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )