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Find the probability as a percent. You flip a coin and toss a 1-6 number cube. P(not heads and not 6)
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Find the probability as a percent. You flip a coin and toss a 1-6 number cube. P(not heads and not 6)
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Mathematics
4 years
2021-08-21T15:12:57+00:00
2021-08-21T15:12:57+00:00 2 Answers
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Answer:
5/6 * 1/2 = 5/12
5/12 = 41.7%
Apologies if this is wrong.
Step-by-step explanation:
Gonna give this my best shot at explaining.
So we know that the probability for flipping a coin is 50/50 because it has two sides. So the probablility here is 1/2. (I’m using fractions to make it easier.)
On a dice it has 6 sides, so the probability of rolling 1-to-6 is 1/6.
Since the probability we are trying to calculate here is not getting heads and not getting a 6. We are left with 1/2 for the coin and 5/6 for the dice.
1/2 is removed from the coin since we don’t need the heads.
And 1/6 is removed from the dice since we don’t need a 6.
Therefore 1/2 mulitplied by 5/6 = 5/12
The percentage is provided at the top.
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