find the polynomial of minimum degree, with real coefficients, zeros at x=-4+1i and x=8, and y intercept at -408

Question

find the polynomial of minimum degree, with real coefficients, zeros at x=-4+1i and x=8, and y intercept at -408

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Diễm Thu 1 year 2021-08-21T22:25:35+00:00 1 Answers 6 views 0

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    2021-08-21T22:27:12+00:00

    Answer:

    (x-8)(x+4-i)=x^2+4x-ix-8x-32+8i=x^2-(4+i)x-32+8i

    y=x^2-(4+i)x-32+8i

    Check:

    D=16+8i-1+128-32i=143-24

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