Find the points of intersection of the graphs involving the following pair of functions. f(x)=2x^2 + 3x – 3 and g(x) = -x^2

Question

Find the points of intersection of the graphs involving the following pair of functions.

f(x)=2x^2 + 3x – 3 and g(x) = -x^2

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Verity 1 month 2021-08-04T08:40:36+00:00 1 Answers 1 views 0

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    2021-08-04T08:42:26+00:00

    Answer:

    The point of intersection is ( \frac{-1\pm\sqrt{5}}{2}, 0)

    Step-by-step explanation:

    f(x) = 2x^2 + 3x – 3 and g(x) = – x^2

    By equating them

    2x^2 + 3x – 3 = -x^2

    3x^2 + 3 x – 3 =  0

    x^2 + x – 1 = 0

    x^2 +x - 1 = 0 \\\\x = \frac{-1\pm\sqrt{5}}{2}

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )