Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating about a perpe

Question

Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating about a perpendicular axis at one end is ml2/3.

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Dulcie 3 weeks 2021-08-30T20:54:15+00:00 1 Answers 0 views 0

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    2021-08-30T20:55:45+00:00

    Answer:

    T = 1.108\,s

    Explanation:

    The period of a physical pendulum is:

    T = \sqrt{\frac{I_{O}}{m\cdot g \cdot L} }

    T=2\cdot \pi \sqrt{\frac{\frac{1}{3}\cdot m \cdot L^{2} }{m\cdot g\cdot L} }

    T=2\cdot \pi \sqrt{\frac{L }{3\cdot g} }

    The length of the leg is approximately the height of the person:

    L = 0.915\,m

    The period is:

    T = 2\cdot \pi \sqrt{\frac{0.915\,m}{3\cdot (9.807\,\frac{m}{s^{2}} )} }

    T = 1.108\,s

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