Find the number of solutions of the equation 6x^2+6x+3=0 by using the discriminant

Question

Find the number of solutions of the equation 6x^2+6x+3=0 by using the discriminant

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Amity 5 months 2021-08-27T21:10:42+00:00 1 Answers 6 views 0

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    2021-08-27T21:11:54+00:00

    Answer:

    No real roots

    Step-by-step explanation:

    Given

    6x^2 + 6x + 3 = 0

    Required

    The number of solution

    The discriminant (d) for ax^2 + bx + c = 0 is:

    d = b^2 - 4ac

    So, we have:

    d = 6^2 - 4*6*3

    d = 36 - 72

    d = -36

    Since d <0, then the equation has no real roots

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )