– Find the missing X- and y-values and Pythagorean triples using the identity (x? y?)2 + (2xy)2 = (x² + y2)2. <

Question

–

Find the missing X- and y-values and Pythagorean triples using the identity

(x? y?)2 + (2xy)2 = (x² + y2)2.

Write the triples in parentheses with commas but no spaces between the values, and order the values

from least to greatest.

Type the correct answer in each box.

in progress 0
Thu Cúc 5 months 2021-08-09T07:53:55+00:00 1 Answers 1 views 0

Answers ( )

  1. minhkhue
    0
    2021-08-09T07:55:25+00:00
    Reply

    Question:

    Find the missing x- and y-values and Pythagorean triples using the identity given

    (x\²-y\²)\² + (2xy)\² = (x\²+y\²)\²

    x = 4

    y = 3

    Pythagorean Triples:

    Write the triples in parentheses with commas but no spaces between the values, and order the values  from least to greatest.

    Answer:

    Pythagorean triples is: (7, 24, 25)

    Step-by-step explanation:

    Pythagorean triples is expressed as:

    a^2 + b^2 = c^2

    In (x\²-y\²)\² + (2xy)\² = (x\²+y\²)\²

    a^2= (x^2 -y^2)^2

    Take square root of both sides

    a = x^2 - y^2

    b^2 = (2xy)^2

    Take square root of both sides

    b = 2xy

    c^2 = (x^2 + y^2)^2

    Take square root of both sides

    c = x^2 + y^2

    So, we have:

    x = 4

    y = 3

    Pythagorean Triples: ?

    a = x^2 - y^2

    a = 4^2 - 3^2

    a = 16 - 9

    a = 7

    b = 2xy

    b = 2 * 4 * 3

    b = 24

    c = x^2 + y^2

    c = 4^2 + 3^2

    c = 16 + 9

    c= 25

    Hence, the Pythagorean triples is: (7, 24, 25)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )