Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.

Question

Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.

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Thạch Thảo 6 months 2021-08-10T05:51:24+00:00 1 Answers 0 views 0

Answers ( )

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    2021-08-10T05:52:58+00:00

    Answer:

    27 feet

    Step-by-step explanation:

    We are told in the question that a lot is rectangular in shape

    The perimeter of a rectangle

    = 2(L + W)

    = 2L + 2W

    Where

    L = Length of the rectangle

    W = Width of the rectangle

    From the question,

    P = 66 feet

    The length is 3 times more than 4 times the width

    L = 3 + (4 × W)

    = 3+ (4W) = 3 + 4W

    Hence,

    P = 2L + 2W

    66 = 2(3 + 4W) + 2W

    66 = 6 + 8W + 2W

    Collect like terms

    66 – 6 = 8W + 2W

    60 = 10 W

    W = 60/10

    W = 6

    The Width of the rectangular lot = 6 feet

    To find the length

    Perimeter = 2L + 2W

    Perimeter – 2W = 2L

    L = Perimeter – 2W/2

    L = 66 – 2(6)/2

    L = 66 – 12/2

    L = 54/2

    L = 27

    Therefore the Length of the rectangular lot = 27 feet

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