## Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.

Question

Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.

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6 months 2021-08-10T05:51:24+00:00 1 Answers 0 views 0

## Answers ( )

27 feet

Step-by-step explanation:

We are told in the question that a lot is rectangular in shape

The perimeter of a rectangle

= 2(L + W)

= 2L + 2W

Where

L = Length of the rectangle

W = Width of the rectangle

From the question,

P = 66 feet

The length is 3 times more than 4 times the width

L = 3 + (4 × W)

= 3+ (4W) = 3 + 4W

Hence,

P = 2L + 2W

66 = 2(3 + 4W) + 2W

66 = 6 + 8W + 2W

Collect like terms

66 – 6 = 8W + 2W

60 = 10 W

W = 60/10

W = 6

The Width of the rectangular lot = 6 feet

To find the length

Perimeter = 2L + 2W

Perimeter – 2W = 2L

L = Perimeter – 2W/2

L = 66 – 2(6)/2

L = 66 – 12/2

L = 54/2

L = 27

Therefore the Length of the rectangular lot = 27 feet