find the x-intercepts y=2x^2 + 5x + 2/x^2-4x+3

Question

find the x-intercepts y=2x^2 + 5x + 2/x^2-4x+3

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Vodka 7 months 2021-07-27T11:43:10+00:00 1 Answers 1 views 0

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    2021-07-27T11:44:53+00:00

    Answer:

    { \tt{y = \frac{2 {x}^{2}  + 5x + 2}{ {x}^{2} - 4x + 3 } }} \\ x - intercept : y = 0 \\ { \tt{ \frac{2 {x}^{2} + 5x + 2 }{ {x}^{2} - 4x + 3  } = 0 }} \\  \\ { \tt{2 {x}^{2}  + 5x + 2 = 0}} \\ x =  \frac{1}{2}  \:  \: and \:  \: x =  - 2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )