find the x-intercepts y=2x^2 + 5x + 2/x^2-4x+3

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find the x-intercepts y=2x^2 + 5x + 2/x^2-4x+3

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Vodka 7 months 2021-07-27T11:43:10+00:00 1 Answers 1 views 0

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  1. mit
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    2021-07-27T11:44:53+00:00
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    Answer:

    { \tt{y = \frac{2 {x}^{2} + 5x + 2}{ {x}^{2} - 4x + 3 } }} \\ x - intercept : y = 0 \\ { \tt{ \frac{2 {x}^{2} + 5x + 2 }{ {x}^{2} - 4x + 3 } = 0 }} \\ \\ { \tt{2 {x}^{2} + 5x + 2 = 0}} \\ x = \frac{1}{2} \: \: and \: \: x = - 2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )