Find the equation of the line that is perpendicular to y = -4x + 3 and contains the point (8, 1).

Question

Find the equation of the line that
is perpendicular to y = -4x + 3
and contains the point (8, 1).

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Verity 6 months 2021-08-04T12:51:39+00:00 2 Answers 4 views 0

Answers ( )

    0
    2021-08-04T12:53:03+00:00

    Answer:

    x-4y=8

    Step-by-step explanation:

    y=mx+c comparing with given eq

    we get slope(m1)=-4

    since both are prependicular

    m1×m2=-1

    -4×m2=-1

    m2=1÷4

    eq:-y-y1=m2 (x-x1)

    y-1=(1÷4)(x-8)

    x-4y=4

    0
    2021-08-04T12:53:32+00:00

    y=1/4x-1

    perpendicular means the y-intercept stays the same (so 3 stays), but the slope would be the opposite reciprocal of the original.

    the opposite of -4 is 4. opposite of negative=positive.

    the reciprocal of 4 is 1/4

    so the new slope is 1/4

    since we have a point, you plus everything on the point slope-form.

    y-y1=m(x-x1)

    (8,1)—> the 8 is x1 and the 1 is y1
    the slope is m

    so it’ll be

    y-1=1/4(x-8)

    solve. first distribute the 1/4

    y -1=1/4x – 2

    add 1 to both sides

    y= 1/4x – 1

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )