Find the distance between the points (2, 4) and (8, -8) on a coordinate plane, to the nearest whole number. A.7 B.11

Question

Find the distance between the points (2, 4) and (8, -8) on a coordinate plane, to the nearest whole number.

A.7
B.11
C.13
D.16

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MichaelMet 3 years 2021-07-16T03:42:42+00:00 1 Answers 35 views 0

Answers ( )

  1. Tryphena
    0
    2021-07-16T03:44:25+00:00
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    Answer:

    C

    Step-by-step explanation:

    distance between two points formula:

    d = \sqrt{( x2 - x1) ^{2} + (y2 - y1) ^{2} }

    where the x and y values are derived from the known points

    we are given the points (2, 4) and (8, -8)

    given these two points let’s define each variable

    x1 = 2

    x2 = 8

    y1 = 4

    y2 = -8

    we now substitute in these values into the formula

    d = \sqrt{(8 - 2) ^{2} + ( - 8 - 4)^{2} }

    now we evaluate the expression using PEMDAS

    first we do the subtraction inside of the parenthesis

    8 – 2 = 6

    -8 – 4 = -12

    d = sqrt(6)^2 + (-12)^2

    next we do the exponents

    6^2 = 36

    -12^2 = 144

    d = sqrt( 144 + 36 )

    next do the addition inside of the parenthesis

    144 + 36 = 180

    d = sqrt ( 180 )

    finally we do the square root of 180

    sqrt ( 180 ) = 13 ( rounded to the nearest whole )

    d = 13

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )