Find the coordinates of the image of the point A(3, 9) for a dilation with the scale factor of 2/3

Question

Find the coordinates of the image of the point A(3, 9) for a dilation with the scale factor of 2/3

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Philomena 2 weeks 2021-09-03T13:24:58+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-03T13:26:24+00:00

    Answer:

    A'(2, 6 )

    Step-by-step explanation:

    Assuming the dilatation is centred at the origin, then multiply each of the coordinates by \frac{2}{3}

    A(3, 9 ) → A'( \frac{2}{3} (3), \frac{2}{3} (9) ) → A'(2, 6 )

    0
    2021-09-03T13:26:37+00:00

    The coordinates of the image of point A(3,9) for dilation with the scale factor of 2/3 will be: A'(2, 6)


    Step-by-step explanation:


    Given the point A with the vertices (3, 9) i.e. A(3,9)


    As we know that If the scale factor is between 0 and 1, the image gets shrunk.


    In order to dilation with a scale factor of 2/3, just multiply the x and y coordinates of the original point (3, 9) by 2/3.


    i.e.


    (x, y) → (2/3 x, 2/3 y)


    so, the coordinates of the image of point A(3,9) for dilation with the scale factor of 2/3 will be:


    A (x, y) → (2/3 x, 2/3 y) = A (2/3 (3), 2/3 (9)) = A'(2, 6)


    Therefore, the coordinates of the image of point A(3,9) for dilation with the scale factor of 2/3 will be: A'(2, 6)

    ( I got it from someone else )

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