Find the center and radius of x^2 + y^2 +6x – 7=0

Question

Find the center and radius of x^2 + y^2 +6x – 7=0

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Bình An 2 weeks 2021-08-29T00:20:35+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-29T00:22:10+00:00

    Answer:

    The center (-3, 0)

    0
    2021-08-29T00:22:29+00:00

    9514 1404 393

    Answer:

    • center: (-3, 0)
    • radius: 4

    Step-by-step explanation:

    The desired parameters can be found by putting the equation into the standard form for the equation of a circle:

      (x -h)^2 +(y -k)^2 = r^2 . . . . . circle centered at (h, k) with radius r

    The values of h and k will be half the coefficients of the linear x- and y-terms, respectively.

      x^2 +6x +9 +y^2 -7 = 9 . . . . . add 9 to complete the square

      (x +3)^2 +y^2 = 16 . . . . . . . . . add 7 to get the desired form

    This equation shows us (h, k) = (-3, 0) and r = 4.

    The center is (-3, 0), and the radius is 4.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )