find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b

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find the area of a rectangle that has a length of 4ab^2 and a width of 6a^2b

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Dulcie 1 year 2021-09-02T14:23:54+00:00 1 Answers 0 views 0

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    2021-09-02T14:25:28+00:00

    Answer:

    Step-by-step explanation:

    ∵A= l×b

    ⇒A= 4ab^2 × 6a^2b

    ⇒A= 24a^2b+1×b^2

    Explanation: When multiplying indices, add the exponents of similar bases (that is, a^2×a = a^2+a^1 =a³) thus a^2b+1.

    I hope this helped.

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