Find an equation of the line that satisfies the given conditions. Through (−3, −6), perpendicular to the line 2x + 5y + 8 = 0

Question

Find an equation of the line that satisfies the given conditions. Through (−3, −6), perpendicular to the line 2x + 5y + 8 = 0

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Minh Khuê 5 months 2021-08-10T01:44:05+00:00 1 Answers 17 views 0

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    2021-08-10T01:45:32+00:00

    Answer:

    Step-by-step explanation:

    Using the point slope equation of a line to solve the question

    y-y0=m(x-x0) where (x0,y0) is the point and m is the slope of the unknown line perpendicular to the given line.

    Rewriting the equation given in the form y = MX+c

    2x+5y+8 = 0

    5y = -8-2x

    y = -8/5-2x/5

    From the equation, m = -2/5

    Since the unknown line is perpendicular to the give line, the slope of the given line will be;

    M = -1/(-2/5)

    M = 5/2

    Substituting the point and the slope into the equation above

    y-(-6) = 5/2(x-(-3))

    y+6 = 5/2(x+3)

    y+6 = 5x/2+15/2

    2y+12 = 5x+15

    2y-5x = 15-12

    2y-5x = 3 gives the required equation of the line

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )