Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)

Question

Find an equation of a line that is parallel to 2x+3y=6 and passes through the point (4, 4)

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RI SƠ 2 weeks 2021-08-28T18:40:56+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-28T18:42:23+00:00

    Answer:

    y = -2/3x + 20/3

    Step-by-step explanation:

    2x + 3y = 6

    3y = -2x + 6

    y = -2/3x + 2

    y = -2/3x + b

    4 = -2/3(4) + b

    4 = -8/3 + b

    20/3 = b

    0
    2021-08-28T18:42:48+00:00

    Answer:

    Answer:

    Step-by-step explanation:

    Slope of a line 2x+3y=6 is -2/3

    So line passing through (0,4) has same slope because both are parallel

    From slope intercept form we have

    Y-y1 =m(x-1)

    Y-4= -2/3(x-0)

    3Y-12 = -2x

    3Y+2x = 12

    Which is required equation of a line.

    Step-by-step explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )