Find an equation for the perpendicular bisector of the line segment whose end points are (-9,-8) and (3,-2)

Question

Find an equation for the perpendicular bisector of the line segment whose end points are (-9,-8) and (3,-2)

in progress 0
Thành Công 3 years 2021-08-24T05:16:47+00:00 1 Answers 1 views 0

Answers ( )

  1. thienhuong
    0
    2021-08-24T05:18:28+00:00
    Reply

    Answer:

    y=-2x-11

    Step-by-step explanation:

    Slope of the line segment = [(-8)-(-2)]/[(-9)-3]=-6/-12=1/2

    Slope of the perpendicular bisector x slope of line segment = -1

    Slope of perpendicular bisector = -2

    Mid-point of line segment = ((-9+3)/2, (-8+(-2))/2) = (-3, -5)

    The perpendicular bisector passes through the mid-point.

    By point-slope form,

    \frac{y-(-5)}{x-(-3)} = -2\\y+5=-2x-6\\y=-2x-11

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )