Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6) Write subtraction of a polynomial expression as addition of the additive invers

Question

Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)

Write subtraction of a polynomial expression as addition of the additive inverse.
(6m5 + 3 – m3 – 4m) + (m5 – 2m3 + 4m – 6)
Rewrite terms that are subtracted as addition of the opposite.
6m5 + 3 + (–m3) + (–4m) + m5 + (–2m3) + 4m + (–6)
Group like terms.
[6m5 + m5] + [3 + (–6)] + [(–m3) + (–2m3)] + [(–4m) + 4m]
Combine like terms.
Write the resulting polynomial in standard form.

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Nem 4 years 2021-08-19T04:33:51+00:00 1 Answers 143 views 0

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    0
    2021-08-19T04:35:04+00:00

    Given:

    The expression is:

    (6m^5+3-m^3-4m)-(-m^5+2m^3-4m+6)

    To find:

    The resulting polynomial in standard form.

    Solution:

    We have,

    (6m^5+3-m^3-4m)-(-m^5+2m^3-4m+6)

    Write subtraction of a polynomial expression as addition of the additive inverse.

    (6m^5+3-m^3-4m)+(m^5-2m^3+4m-6)

    Rewrite terms that are subtracted as addition of the opposite.

    6m^5+3+(-m^3)+(-4m)+m^5+(-2m^3)+4m+(-6)

    Group like terms.

    [6m^5+m^5]+[3+(-6)]+[(-m^3)+(-2m^3)]+[(-4m)+4m]

    Combine like terms.

    7m^5+(-3)+(-3m^3)+0

    On simplification, we get

    7m^5-3-3m^3

    Write the polynomial in standard form.

    7m^5-3m^3-3

    Therefore, the required polynomial in standard form is 7m^5-3m^3-3.

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