Falling objects drop with an average acceleration of 9.8 m/s2. An arrow is shot with a velocity of 11.76 m/s straight down from the top of a

Question

Falling objects drop with an average acceleration of 9.8 m/s2. An arrow is shot with a velocity of 11.76 m/s straight down from the top of a tall castle hitting an armored knight with a downward velocity of 49 m/s. How long was the arrow in flight?

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Nem 19 hours 2021-07-21T13:07:09+00:00 1 Answers 0 views 0

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    2021-07-21T13:08:18+00:00

    Answer:

    3.8 secs

    Explanation:

    Parameters given:

    Acceleration due to gravity, g = 9.8 m/s^2

    Initial velocity, u = 11.76 m/s

    Final velocity, v = 49 m/s

    Using one of Newton’s equations of linear motion, we have that:

    v = u + gt

    where t = time of flight of arrow

    The sign is positive because the arrow is moving downward, in the same direction as gravitational force.

    Therefore:

    49 = 11.76 + 9.8*t\\\\\\\49 - 11.76 = 9.8t\\\\=> 9.8t = 37.24\\\\\\t = \frac{37.24}{9.8} \\\\\\t = 3.8 secs

    The arrow was in flight for 3.8 secs

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