Factor the following polynomial 9×2 + 21x – 18

Question

Factor the following polynomial 9×2 + 21x – 18

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Gerda 3 days 2021-07-21T23:21:05+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-21T23:22:33+00:00

    Answer:

    factors are

    21 and x

    Step-by-step explanation:

    equation 9 × 2 + 21x – 18

    terms 9 , 2, 21x, -18

    factors 21x = 21 and x

    0
    2021-07-21T23:22:48+00:00

    Answer:

    3(x + 3)(3x – 2)

    Step-by-step explanation:

    Given

    9x² + 21x – 18 ← factor out 3 from each term

    = 3(3x² + 7x – 6) ← factor the quadratic

    Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

    product = 3 × – 6 = – 18 and sum = + 7

    The factors are + 9 and – 2

    Use these factors to split the x- term

    3x² + 9x – 2x – 6 ( factor first/second and third/fourth terms )

    3x(x + 3) – 2(x + 3) ← factor out (x + 3) from each term

    (x + 3)(3x – 2)

    Then

    9x² + 21x – 18 = 3(x + 3)(3x – 2) ← in factored form

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )