F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointing upwards.

Question

F = xi+yj+2zk and σ is the portion of the cone z=x2+y2−−−−−−√ between the planes z=4 and z=5 oriented with normal vectors pointing upwards. Find the flux of the flow field F across σ

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Trúc Chi 4 years 2021-08-27T23:21:01+00:00 1 Answers 14 views 0

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  1. Nho
    0
    2021-08-27T23:22:14+00:00
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    there is no question for me to answer

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