f(x) = -1/2x^2 + 3/2x – 2 I need to find the zeros​

Question

f(x) = -1/2x^2 + 3/2x – 2 I need to find the zeros​

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bonexptip 6 months 2021-07-15T13:42:17+00:00 1 Answers 1 views 0

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    2021-07-15T13:44:07+00:00

    Answer:

    {-1, 4}

    Step-by-step explanation:

    In the given f(x) = -1/2x^2 + 3/2x – 2

    set f(x) = 0 and then multiply all the numeric terms by -2 to remove the fractions:

    f(x) = -1/2x^2 + 3/2x – 2 = 0  =>  1x^2 – 3x – 4 = 0  

    This factors into (x – 4)(x + 1) = 0, whose roots are {-1, 4}.  These are the zeros.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )