Eva bought popcorn, candy and a drink at the movies. The popcorn was three times as expensive as the candy and the drink was twice

Question

Eva bought popcorn, candy and a drink at the movies. The popcorn was three times as expensive as the candy and the drink was twice as expensive as the candy. Eva spent a total of 10.50

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Yến Oanh 18 mins 2023-01-13T05:15:47+00:00 1 Answer 0 views 0

Answer ( 1 )

  1. niczorrrr
    0
    2023-01-13T05:17:45+00:00
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    The cost of popcorn, drinks, and candy is 5.25, 3.5, and 1.75.
    Given,
    Eva bought popcorn, candy, and a drink at the movies.
    The popcorn was three times as expensive as the candy and the drink was twice as expensive as the candy.
    Eva spent a total of 10.50
    We need to find the cost of popcorn, candy, and drink.
    We have,
    Let the cost of the candy be C.
    Now,
    The popcorn was three times as expensive as the candy.
    Cost of the Popcorn = 3C
    The drink was twice as expensive as the candy.
    Cost of the drink = 2C
    Eva spent a total of 10.50
    Cost of popcorn + cost of drink + cost of candy = 10.50
    3C + 2C + C = 10.50
    Adding
    6C = 10.50
    Dividing by 6 into both sides
    C = 10.50/6
    C = 1.75.
    Now,
    Cost of the Popcorn = 3C = 3 x 1.75 = 5.25
    Cost of the drink = 2C = 2 x 1.75 = 3.5
    Cost of the candy = C = 1.75
    Thus the cost of popcorn, drinks, and candy is 5.25, 3.5, and 1.75.
    Learn more about finding the cost of items with the given total cost here:
    #SPJ1

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