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(Easy) For the following quadratic function, find the axis of symmetry, the vertex and the y-intercept. y = x^2 + 12x + 32
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(Easy) For the following quadratic function, find the axis of symmetry, the vertex and the y-intercept. y = x^2 + 12x + 32
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Mathematics
3 years
2021-08-23T09:02:04+00:00
2021-08-23T09:02:04+00:00 2 Answers
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Answer:
Answer:
see explanation
Step-by-step explanation:
Given a quadratic in standard form , y = ax² + bx + c ( a ≠ 0 ), then
The x- coordinate of the vertex, which is also the equation of the axis of symmetry is
= –
y = x² + 12x + 32 ← is in standard form
with a = 1, b = 12 , then
= – = – 6
Substitute x = – 6 into y for corresponding y- coordinate
y = (- 6)² + 12(- 6) + 32 = 36 – 72 + 32 = – 4
Thus
equation of axis of symmetry is x = – 6
vertex = (- 6, – 4 )
To find the y- intercept , let x = 0
y = 0² + 12(0) + 32 = 32 ← y- intercept