During an earthquake, the top of a building oscillates with an amplitude of 30cm at 1.5Hz. Part A What is the magnitude of the maximum

Question

During an earthquake, the top of a building oscillates with an amplitude of 30cm at 1.5Hz.
Part A What is the magnitude of the maximum displacement from the equilibrium of the top of the building? (in cm)
Part B What is the maximum velocity of the top of the building?(in cm/s)
Part C What is the maximum acceleration of the top of the building?(in cm/s^2

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Khoii Minh 5 months 2021-08-04T07:30:28+00:00 1 Answers 8 views 0

Answers ( )

    0
    2021-08-04T07:31:33+00:00

    A.30cm

    B.282.7cm/s

    C.26655cm/s²

    Explanation:

    A. Maximum displacement= Amplitude= 0.3m

    B.mum velocity=

    2πAf= 2π x 1.5×30 =282.7cm/s

    C. Maximum acceleration

    = ( angular velocity)² A= (2πf)² A

    =( 2 x 3.142 x 1.5)² x 30

    2665.5cm/s²

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