During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintained her velocity for another 10 seconds (in m)?
During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintained her velocity for another 10 seconds (in m)?
Explanation:
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Answer:
Explanation:
Given that
Total race distance is 400m
Her initial velocity was 0m/s²
At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²
Using equation of motion
Let determine her constant acceleration
v²=u²+2as
12²=0²+2×a×100
144=0+200a
144=200a
a=144/200
a=0.72m/s²
Then we want to know her position after another 10second
So total time is 10+12=22seconds
Then, using equation of motion
Let determine his postion
S=ut+½at²
S=0•t+½×0.72×22²
S=0+174.24
S=174.24 m
Her position will be 174.24m