Dichlorine monoxide, Cl2O is sometimes used as a powerful chlorinating agent in research. It can be produced by passing chlorine gas over h

Question

Dichlorine monoxide, Cl2O is sometimes used as a powerful chlorinating agent in research. It can be produced by passing chlorine gas over heated mercury (II) oxide according to the following equation: HgO + Cl2 ????HgCl2 + Cl2O What is the percent yield, if the quantity of the reactants is sufficient to produce 0.86g of Cl2O but only 0.71 g is obtained?

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Thiên Hương 4 years 2021-07-16T23:51:47+00:00 1 Answers 72 views 0

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  1. diemkieu
    0
    2021-07-16T23:53:06+00:00
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    Answer:

    % yield =  82.5%

    Explanation:

    HgO + 2Cl₂ →  HgCl₂ +  Cl₂O

    Our reactants are:

    • HgO and Cl₂

    Our products are:

    • HgCl₂ +  Cl₂O

    We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.

    Percent yield = (Yield produced / Theoretical yield) . 100

    Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:

    % yield = (0.71 g/0.86g) . 100 = 82.5%

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )