Determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E].

Question

Determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E].

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Delwyn 3 days 2021-07-22T23:01:19+00:00 1 Answers 1 views 0

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    2021-07-22T23:02:50+00:00

    Answer:

    3.44 metres

    Explanation:

    To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x – component and y – component.

    Resolving into x – component

    – 2.4cos32 + 4.9cos27 = 2.3306

    Resolving into y – component

    – 2.4sin32 – 4.9sin27 – 1.6 = – 2.553

    The vector sum of the displacement will be

    Sqrt( 2.3^2 + 2.6^2) =

    Sqrt ( 11.81)

    3.44 m

    Therefore, the vector sum of the displacements is 3.44 metres

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