. Determine the temperature of .084 moles of CO2 gas at 790 mmHg which occupies a volume of 2.1L

Question

.
Determine the temperature of .084 moles of CO2 gas at 790 mmHg
which occupies a volume of 2.1L

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Ngọc Diệp 3 months 2021-08-22T12:02:45+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-22T12:03:51+00:00

    Answer:

    Explanation:

    ideal gas law: PV=nRT

    n=0.084 mole

    P=790mmHg

    V=2.1L

    Substituting into the eqn, T=316.7K

    0
    2021-08-22T12:03:58+00:00

    Answer:

    Explanation:

    Molar volume at STP = 22.4L

    So 0.084 mole of CO2 at STP has volume of 22.4*0.084 = 1.882L

    Combined Gas Law: P1V1/T1 = P2V2/T2

    760*1.882/273 = 790*2.1/Temperature

    Temperature = 790*2.1*273/760/1.882

    = 316.6K

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