Determine the pH of a 2.8 ×10−4 M solution of Ca(OH)2.

Question

Determine the pH of a 2.8 ×10−4 M solution
of Ca(OH)2.

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Tài Đức 1 year 2021-09-02T06:44:27+00:00 1 Answers 4 views 0

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    2021-09-02T06:46:05+00:00

    Answer:

    pH = 10.75

    Explanation:

    To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

    Using the equation:

    pH = 14 – pOH

    We can find the pH of the solution.

    The molarity of Ca(OH)₂ is 2.8×10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8×10⁻⁴M = 5.6×10⁻⁴M

    pOH is

    pOH = -log 5.6×10⁻⁴M

    pOH = 3.25

    pH = 14-pOH

    pH = 10.75

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )