Determine the concentration of strontium ions in saturated solution of strontium sulfate, SrSO4, if the Ksp for SrSO4 is 3.2×10-7.

Question

Question

in progress 0

Chemistry RI SƠ 5 months 2021-09-02T21:20:13+00:00 2021-09-02T21:20:13+00:00 1 Answers 0 views 0

Answers ( )

Name*

E-Mail*

Website

Featured image

Browse

Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

Answer*

danthu · Answer 1 · 2021-09-02T21:21:39+00:00

danthu

0

2021-09-02T21:21:39+00:00 September 2, 2021 at 9:21 pm

Reply

Answer:

$[Sr^{2+}]=5.66x10^{-4}M$

Explanation:

Hello there!

In this case, given the solubility equilibrium of strontium sulfate:

$SrSO_4(s)\rightleftharpoons Sr^{2+}(aq)+SO_4^{2-}(aq)$

Whose equilibrium expression is:

$Ksp=[Sr^{2+}][SO_4^{2-}]$

In such a way, we can introduce the molar solubility, s, in the equation to obtain:

$Ksp=s*s=s^2\\\\3.2x10^{-7}=s^2$

Then, we apply the square root to obtain:

$s=\sqrt{3.2x10^{-7}}\\\\s=5.66x10^{-4}M$

Which is also the concentration of strontium ions:

$[Sr^{2+}]=5.66x10^{-4}M$

Best regards!