Determine the concentration of strontium ions in saturated solution of strontium sulfate, SrSO4, if the Ksp for SrSO4 is 3.2×10-7.​

Question

Determine the concentration of strontium ions in saturated solution of strontium sulfate, SrSO4, if the Ksp for SrSO4 is 3.2×10-7.​

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RI SƠ 5 months 2021-09-02T21:20:13+00:00 1 Answers 0 views 0

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    2021-09-02T21:21:39+00:00

    Answer:

    [Sr^{2+}]=5.66x10^{-4}M

    Explanation:

    Hello there!

    In this case, given the solubility equilibrium of strontium sulfate:

    SrSO_4(s)\rightleftharpoons Sr^{2+}(aq)+SO_4^{2-}(aq)

    Whose equilibrium expression is:

    Ksp=[Sr^{2+}][SO_4^{2-}]

    In such a way, we can introduce the molar solubility, s, in the equation to obtain:

    Ksp=s*s=s^2\\\\3.2x10^{-7}=s^2

    Then, we apply the square root to obtain:

    s=\sqrt{3.2x10^{-7}}\\\\s=5.66x10^{-4}M

    Which is also the concentration of strontium ions:

    [Sr^{2+}]=5.66x10^{-4}M

    Best regards!

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