## Describe different types of motion with examples. (4) (b) difference between scalar and vector. (2) (c) A car has a

Question

Describe different types of motion with examples. (4)

(b) difference between scalar and vector. (2)

(c) A car has a velocity of 10 ms-1

. It accelerates at 0.2 ms-2

for half minute. Find the distance​

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3 months 2021-08-02T18:28:08+00:00 2 Answers 3 views 0

300 meters is correct

Explanation:

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a)

there r two types of motion, uniform and non-uniform

uniform means equal distance travelled at equal intervals of time

and non-uniform is exactly the opposite.

b)

quantities which can be represented by magnitude along r called scalar quantities such as speed.

quantities which need magnitude along with direction r called vector quantities such as velocity.

c)

velocity=10m/s

acceleration = u-v/s i.e initial final velocity – initial velocity upon time

acceleration= 0.2m/s sq

time= 30s

10 = displacement/time

10 = x/30

10 = 300

Answer is 300 meters – distance/displacement.