## Daniel expanded the expression as shown -3(-8x-4y+3/4)=10x-8y-1 1/4 what areas did he make like three options

Question

Daniel expanded the expression as shown -3(-8x-4y+3/4)=10x-8y-1 1/4 what areas did he make like three options

in progress 0
1 year 2021-08-09T00:22:24+00:00 1 Answers 249 views 0

1. Question

Daniel expanded the expression as shown. What errors did he make? Select three options.

$$-2(-8x-4y+3/4)=-10x-8y-1 \frac{1}{4}$$

A. The first term should be positive.

B. The second term should be positive.

C. The last term should be -1 1/2, not -1 1/4.

D. He divided -8 by -2 instead of multiplying -8 by -2.

E. He did not simplify the expression completely.

Daniel’s errors are (a), (b) and (c)

Step-by-step explanation:

To do this, we only need to solve the expression on the left.

So, we have:

$$-2(-8x-4y+3/4)=$$

Open bracket

$$-2(-8x-4y+3/4)=-2 * -8x -2 * -4y – 2 * 3/4$$

$$-2(-8x-4y+3/4)=16x + 8y – \frac{2 * 3}{4}$$

$$-2(-8x-4y+3/4)=16x + 8y – \frac{6}{4}$$

$$-2(-8x-4y+3/4)=16x + 8y – 1\frac{1}{2}$$

From the expression, we can see that:

• The first term is positive
• The second is also positive
• And the third term is$$- 1\frac{1}{2}$$

So, Daniel’s errors are (a), (b) and (c)