constant force F=5i+5j−1kF=5i+5j−1k is applied to an object that is moving along a straight line from the point (−5,−3,−4)(−5,−3,−4) to the

Question

constant force F=5i+5j−1kF=5i+5j−1k is applied to an object that is moving along a straight line from the point (−5,−3,−4)(−5,−3,−4) to the point (2,5,0).(2,5,0). Find the work done if the distance is measured in meters and the force in newtons. Include units in your answer.

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Gerda 4 years 2021-08-09T19:49:22+00:00 1 Answers 11 views 0

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    2021-08-09T19:50:40+00:00

    Answer:

    W = 71J

    Explanation:

    Given force F = (5i+5j−1k)N

    d = Δr

    r1 = (−5,−3,−4)m

    r2 = (2,5,0)m

    Δr = r2 – r1 = (2-(-5), 5-(-3), 0-(-4))

    Δr = (2+5, 5+3, 0+4) = (7i+ 8j +4k)m

    W = F•d = (5i+5j−1k)•(7i+ 8j +4k)

    W = 5×7 + 5×8 +-1×4 = 35 + 40 – 4

    W = 71J

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