Consider the reaction 2 NO2 (g) <=> N2O4 If the equilibrium concentration of both NO2 and N2O4 are 0.2

Question

Consider the reaction

2 NO2 (g) <=> N2O4

If the equilibrium concentration of both NO2 and N2O4 are 0.2 M, what is the value of Kc?

A. 0.2

B. 0.3

C. 0.225

D. 5.0

E. 2.5

Please help.

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Gia Bảo 2 weeks 2021-09-02T20:40:59+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-02T20:42:17+00:00

    Answer:

    D. 5.0

    Explanation:

    Step 1: Write the balanced equation at equilibrium

    2 NO₂(g) ⇄ N₂O₄(g)

    Step 2: Calculate the concentration equilibrium constant

    The concentration equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

    Kc = [N₂O₄]/[NO₂]² = 0.2 / 0.2² = 5

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )