Consider the polynomial 16×2 – 1. What is the value of ac? What is the value of b?

Question

Consider the polynomial 16×2 – 1.

What is the value of ac?

What is the value of b?

What two numbers multiply to get ac and add to get b?

The factored form of 16×2 – 1 is

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Latifah 4 years 2021-09-03T08:42:07+00:00 1 Answers 68 views 0

Answers ( )

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    2021-09-03T08:44:06+00:00

    9514 1404 393

    Answer:

    • ac = -16
    • b = 0
    • -4, 4
    • (4x -1)(4x +1)

    Step-by-step explanation:

    a) ac is the product of the leading coefficient (16) and the constant (-1).

      ac = (16)(-1) = -16

    __

    b) b is the coefficient of x. There is no x term, so …

      b = 0

    __

    c) Two factors that add to give zero must be opposites. That is, they must be the square root of the opposite of -16, and the opposite of that.

      the two numbers are -4 and 4

    __

    d) The factored form for the two numbers p and q just found is …

      ax^2 +bx +c = (ax +p)(ax +q)/a

      = (16x -4)(16x +4)/16

      = (4x -1)(4x +1) . . . . factored form of 16x^2 -1

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )