Consider the line y=-5/6x-4. Find the equation of the line that is parallel to this line and passes through the point (-6,-2).

Question

Consider the line y=-5/6x-4.
Find the equation of the line that is parallel to this line and passes through the point (-6,-2).

Find the equation of the line that is perpendicular to this line and passes through the point (-6,-2).

in progress 0
Lệ Thu 4 years 2021-07-18T10:21:32+00:00 1 Answers 56 views 0

Answers ( )

  1. Philomena
    0
    2021-07-18T10:22:57+00:00
    Reply

    Answer:

    Lines that are parallel have the same gradient.

    Since the line is y=-5/6x-4,the gradient of the line parallel to this line is also -5/6.

    So the equation of the line parallel to y=-5/6x-4 is y-(-2)=-5/6(x-(-6))—>y=-5/6x-7.

    Lines that are perpendicular fulfill the requirement: gradient 1×gradient 2=-1 . Then once you find the gradient of the line, you can find the equation of the line.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )