Consider a system of two particles: ball A with a mass m is moving to the right a speed 2v and ball B with a mass 3m is moving to the left a

Question

Consider a system of two particles: ball A with a mass m is moving to the right a speed 2v and ball B with a mass 3m is moving to the left at a speed v. In the time interval before the two balls collide, what is the magnitude and the direction of the velocity of the center of mass of this system?

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Thành Công 2 weeks 2021-07-19T06:31:54+00:00 1 Answers 1 views 0

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    2021-07-19T06:33:02+00:00

    Answer:

    Explanation:

    Answer:

    Explanation:

    Given that,

    System of two particle

    Ball A has mass

    Ma = m

    Ball A is moving to the right (positive x axis) with velocity of

    Va = 2v •i

    Ball B has a mass

    Mb = 3m

    Ball B is moving to left (negative x axis) with a velocity of

    Vb = -v •i

    Velocity of centre of mass Vcm?

    Velocity of centre of mass can be calculated using

    Vcm = 1/M ΣMi•Vi

    Where M is sum of mass

    M = M1 + M2 + M3 +…

    Therefore,

    Vcm=[1/(Ma + Mb)] × (Ma•Va +Mb•Vb

    Rearranging for better understanding

    Vcm = (Ma•Va + Mb•Vb) / ( Ma + Mb)

    Vcm = (m•2v + 3m•-v) / (m + 3m)

    Vcm = (2mv — 3mv) / 4m

    Vcm = —mv / 4m

    Vcm = —v / 4

    Vcm = —¼V •i

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )