Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radiu

Question

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.

The radius of the circle is 3 units.

The center of the circle lies on the x-axis.

The center of the circle lies on the y-axis.

The standard form of the equation is (x – 1)² + y² = 3.

The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

in progress 0
Gerda 1 month 2021-07-31T03:53:34+00:00 2 Answers 12 views 0

Answers ( )

    0
    2021-07-31T03:55:14+00:00

    Answer:

    The first, second, and fifth statements are correct.

    Step-by-step explanation:

    i got it right on edg if right mark as brainliest

    0
    2021-07-31T03:55:25+00:00

    Answer:

    The first, second, and fifth statements are correct.

    Step-by-step explanation:

    We are given a circle with the equation:

    x^2+y^2-2x-8=0

    And we want to select the statements that are true.

    First, we can convert the equation into standard form. We can group each variable:

    (x^2-2x)+(y^2)=8

    And complete the square for the first term:

    (x^2-2x+1)+(y^2)=8+1

    Factor and simplify:

    (x-1)^2+y^2=9

    We can rewrite our equation as:

    (x-(1))^2+(y-(0))^2=(3)^2

    So, this tells us that we have a circle centered on (1, 0) with a radius of 3 units.

    In this case, the first statement, second statement (the point (1,0) is on the x-axis), and fifth statements are correct (the square root of 9 is also 3).

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )