Complete the square for the following quadratic equation to determine its solutions and the location of its extreme value. y=-x^

Question

Complete the square for the following quadratic equation to determine its solutions and the location of its extreme value.

y=-x^2+4x+12

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Kiệt Gia 2 months 2021-07-29T09:19:54+00:00 1 Answers 7 views 0

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    2021-07-29T09:21:53+00:00

    Answer:

    x^2+4x+12=(x+3)^2+3

    Step-by-step explanation:

    x^2+4x+12

    (1/2×6)^2=(3)^2=9

    x^2+4x+(3)^2-(3)^2+12

    x^2+4x+9-9+12

    (x+3)^2-9+12

    (x+3)^2+3

    hope I helped.

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