## Choose the correct answer 1- A car travelled 60 km east in 1.33 h along a straight line, then returned back west for 40 km in 0.

Question

1- A car travelled 60 km east in 1.33 h along a straight line, then returned back west for 40 km
in 0.67 h. Its average velocity is:
a) 10 km/h, east. b) 10 km/h, west. c) 50 km/h, east. d) 50 km/h, west.

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6 months 2021-07-27T08:21:00+00:00 1 Answers 6 views 0

The average velocity has magnitude = 10 km/h , direction: east

Explanation:

In order to find the average velocity of the car we need to know the final and initial positions, and the time that took to get from one to the other.

Notice that since its movement was 60 km straight east and then from there 40 km straight west, the car is positioned at 20 km to the east of its initial departure point. therefore the vector change in position is a vector 20 km in magnitude, and direction towards the east.

Since it took the car a total of 1.33 hours plus 0.67 hours to reach its final position, the total time elapsed is: 1.33 + 0.67 hours = 2 hours.

Then,the velocity vector has magnitude; 20 km / 2 hours = 10 km/hour

As we mentioned above. the direction of the velocity vector is east.