Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là

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Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là

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Edana Edana 6 months 2021-07-17T07:34:46+00:00 1 Answers 1438 views 0

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    2021-07-17T07:36:30+00:00

    Answer: The mass of FeO required is 14.37 g

    Explanation:

    Molarity is calculated by using the equation:

    \text{Molarity}=\frac{\text{Moles}}{\text{Volume}} ……(1)

    We are given:  

    Molarity of iron (II) sulfate = 1 M

    Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

    Putting values in equation 1, we get:

    \text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol

    The chemical equation for the reaction of FeO with sulfuric acid follows:

    FeO+H_2SO_4\rightarrow FeSO_4+H_2O

    By stoichiometry of the reaction:

    If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

    So, 0.200 moles of iron (II) sulfate will produce = \frac{1}{1}\times 0.200=0.200mol of FeO

    The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

    \text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

    We know, molar mass of FeO = 71.84 g/mol

    Putting values in above equation, we get:

    \text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g

    Hence, the mass of FeO required is 14.37 g

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