Charlie runs an auto repair and mechanic shop. A hot rod has come in with mass 1500 kg requiring a repair. He needs to raise the car using a

Question

Charlie runs an auto repair and mechanic shop. A hot rod has come in with mass 1500 kg requiring a repair. He needs to raise the car using a hydraulic lift on a piston (Piston A) having a radius of 25 cm. What force needs to be applied to the opposing 1.0 cm radius piston (Piston B) to accomplish this? Ignore the weight of the pistons.

in progress 0
Ngọc Hoa 1 day 2021-07-21T21:58:20+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-21T21:59:43+00:00

    Answer:

    23.52 N

    Explanation:

    Using the Hydraulic Press formula

    since the the liquid in an hydraulic press cannot be compressed

    P₁ ( pressure at the piston 1) = P₂ ( pressure at piston 2)

    P₁ = F₁ / A₁ where F₁ represent the weight of the car and F₂ represent the force applied at the 1 cm end and A₁ and A₂ are the area of the piston respectively

    P₂ = F₂ / A₂

    F₁ / A₁ = F₂ / A₂

    (F₁/A₁) × A₂ = F₂

    F₁ = 1500 kg × 9.8 m/s² = 14700 N

    A₁ = πR² = π ( 0.25)²  where R = 25 cm = 0.25 m for the larger piston

    A₂ = πr² = π ( 0.01)²   where r = 1 cm = 0.01 m

    (F₁/A₁) × A₂ = F₂

    F₂ = ( 14700 N / ( π 0.0625)) ×π (0.01)² = 23.52 N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )