Charge is placed on two conducting spheres that are very far apart and connected by a long thin wire. The radius of the smaller sphere is 5

Question

Charge is placed on two conducting spheres that are very far apart and connected by a long thin wire. The radius of the smaller sphere is 5 cm and that of the larger sphere is 12 cm. The electric field at the surface of the larger sphere is 660 kV/m. Find the surface charge density on each sphere.

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Kim Chi 4 years 2021-08-22T22:33:42+00:00 1 Answers 2 views 0

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  1. ThanhThu
    0
    2021-08-22T22:35:31+00:00
    Reply

    Answer:

    surface charge density on each sphere is 440 \times 10^{-9} C

    Explanation:

    given data

    radius of smaller sphere = 5 cm

    radius of  larger sphere is 12 cm

    electric field at surface of larger sphere = 660 kV/m = 660 × 1000 v/m

    solution

    we apply here electric field formula that is express as

    E = (\frac{1}{4\pi\epsilon })\times (\frac{Q_{1} }{R^{2} } )    ……………..1

    put here value

    660000 = 9 \times 10^9 \times \frac{Q1}{0.12^2}  

    Q1 = 1056 × 10^{-9}

    and

    here field inside a conductor is zero so that electric potential ( V ) is constant

    \frac{Q{1} }{R} = \frac{Q{2} }{r}   ………………2

    so Q2 will be

    Q2 =  \frac{5}{12} \times 1056 \times 10^{-9}  

    Q2 =  440 \times 10^{-9}  C

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