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Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this problem. Car A use
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Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this problem. Car A uses tires for which the coefficient of static friction is 0.335 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is 26.8 m/s. Car B uses tires for which the coefficient of static friction is 0.683 on the same curve. What is the maximum speed at which car B can negotiate the curve?
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Physics
4 years
2021-07-17T11:20:28+00:00
2021-07-17T11:20:28+00:00 1 Answers
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Answer:
Explanation:
The question relates to motion on a circular path .
Let the radius of the circular path be R .
The centripetal force for circular motion is provided by frictional force
frictional force is equal to μmg , where μ is coefficient of friction and mg is weight
Equating cenrtipetal force and frictionl force in the case of car A
mv² / R = μmg
R = v² /μg
= 26.8 x 26.8 / .335 x 9.8
= 218.77 m
In case of moton of car B
mv² / R = μmg
v² = μRg
= .683 x 218.77x 9.8
= 1464.35
v = 38.26 m /s .