Certain neutron stars (extremely dense stars) are believed to be rotating at about 0.83 rev/s. If such a star has a radius of 40 km, what mu

Question

Certain neutron stars (extremely dense stars) are believed to be rotating at about 0.83 rev/s. If such a star has a radius of 40 km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation? Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement

in progress 0
Hưng Khoa 7 months 2021-07-20T12:43:58+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-20T12:45:35+00:00

    Answer:

    The mass of the star would be  M = 2.644*10^{24} \ kg    

    Explanation:

    From the question we are told that

         The angular speed is  w = 0.83\  rev/s =  0.83 * 2 \pi = 1.66 rad/s

          The radius of the star is  r = 40km = 40 *1000 = 40 * 10^{3} m    

         

    Generally the minimum mass of the start is mathematically evaluated as

                 M = \frac{r^3 w^2}{G}

    Where is the gravitational constant with a values of  G  = 6.67*10^{-11} N \cdot m^2 /kg

                 M = \frac{(40*10^3)^3 * 1.66^2}{6.67*10^{-11}}

                 M = 2.644*10^{24} \ kg    

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )